16x^2+184x=-525

Solution for 16x^2+184x=-525 equation:

16x^2+184x=-525

We move all terms to the left:

16x^2+184x-(-525)=0

We add all the numbers together, and all the variables

16x^2+184x+525=0

a = 16; b = 184; c = +525;
Δ = b2-4ac
Δ = 1842-4·16·525
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(184)-16}{2*16}=\frac{-200}{32}
=-6+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(184)+16}{2*16}=\frac{-168}{32}
=-5+1/4
$